Đề kiểm tra Giữa kì 2 Toán 12 có đáp án (Mới nhất) (Đề 4)

$x^2-\frac{3}{x}+C$

$x^2+\frac{3}{x^2}+C$

$x^2+3\ln x^2+C$

$x^2+\frac{3}{x}+C$

$-\frac{1}{6}\sin 6x+\frac{1}{4}\sin 4x+C$

$6\sin 6x-5\sin 4x+C$

$\frac{1}{6}\sin 6x-\frac{1}{4}\sin 4x+C$

$-6\sin 6x+\sin 4x+C$

$F\left(x\right)=\frac{{\cos }^{5}x}{5}+C$

$F\left(x\right)=\frac{{\cos }^{4}x}{4}+C$

$F\left(x\right)=\frac{{\sin }^{4}x}{4}+C$

$F\left(x\right)=\frac{{\sin }^{5}x}{5}+C$

$\{\begin{array}{c}u=x\\ \text{d}v=\ln \left(2+x\right)\text{d}x\end{array}.$

$\{\begin{array}{c}u=\ln \left(2+x\right)\\ \text{d}v=x\text{d}x\end{array}.$

$\{\begin{array}{c}u=x\ln \left(2+x\right)\\ \text{\hspace{0.17em}d}v=\text{d}x\end{array}.$

$\{\begin{array}{c}u=\ln \left(2+x\right)\\ \text{d}v=\text{d}x\end{array}.$

$I=e^x+x{e}^x+C$

$I=\frac{x^2}{2}{e}^x+C$

$I=x{e}^x-e^x+C$

$I=\frac{x^2}{2}{e}^x+e^x+C$

5

1

-1

-5

$\underset{a}{\overset{a}{\int }}f\left(x\right)dx=1$

$\underset{a}{\overset{a}{\int }}f\left(x\right)dx=0$

$\underset{a}{\overset{a}{\int }}f\left(x\right)dx=-1$

$\underset{a}{\overset{a}{\int }}f\left(x\right)dx=f\left(a\right)$

3

0

-2

-4

$\frac{\pi }{4}$

$\frac{\pi }{2}$

$\frac{\pi }{6}+1$

$\frac{\pi }{12}+\text{}1$

$\frac{19}{8}$

$\frac{23}{8}$

$\frac{21}{8}$

$\frac{25}{8}$

$\frac{1}{420}$

$\frac{1}{380}$

$\frac{1}{342}$

$\frac{1}{462}$

9

3

27

81

-1

1

2

0

I = cos1

I = 1

I = sin1

Một kết quả khác

${\pi }^2-4$

${\pi }^2+4$

$2{\pi }^2-3$

$2{\pi }^2+3$

$\frac{1}{2}\left(1+\ln 2\right)$

$\frac{1}{2}\left(1-\ln 2\right)$

$\frac{1}{2}\left(\ln 2-1\right)$

$\frac{1}{4}\left(1+\ln 2\right)$

4

3

5

6

2

-7

7

-2

$e-2$

$e$

$e+1$

$1-e$

$\pi$

$2\pi$

$\frac{6\pi }{7}$

$\frac{2\pi }{7}$

$\frac{25}{33}$

$\frac{5}{4}$

$\frac{1}{2}$

$\frac{53}{50}$

$I=\frac{1186}{45}$

$I=\frac{1174}{45}$

$I=\frac{1222}{45}$

$I=\frac{1201}{45}$

$\left(8;-12;5\right)$

$\left(8;-12;0\right)$

$\left(0;8;12\right)$

$\left(0;8;-12\right)$

$\left(\frac{17}{25};\frac{49}{50};0\right)$

$\left(-3;-6;7\right)$

$\left(-1;-13;14\right)$

$\left(\frac{4}{7};\frac{13}{14};0\right)$

$M\left(0;0;3\right)$

$M\left(0;0;2\right)$

$M\left(0;0;-3\right)$

$M\left(0;3;0\right)$

$\frac{2}{5}$

$\frac{-2}{5}$

$\frac{1}{5}$

1

$G\left(-\frac{3}{2};3;0\right).$

$G\left(-3;6;0\right).$

$G\left(-1;2;0\right).$

$G\left(-\frac{1}{3};\frac{2}{3};0\right).$

$2\sqrt{7}$

$\sqrt{29}$

$3\sqrt{3}$

$\sqrt{30}$

m = 3

m = -3

m = 4

m = -4

$m=\frac{7}{3}$

$m=\frac{1}{2}$

$m=\frac{3}{7}$

$m=\frac{2}{7}$

$x_o+y_o+z_o=3$

$x_o+y_o+z_o=-3$

$x_o+y_o+z_o=6$

$x_o+y_o+z_o=-6$

$m\ne \frac{5}{2}$

$m\ne \frac{2}{5}$

$m\in \varnothing$

$m\ne 3$

và

và

và

và

$12\sqrt{3}$

$6\sqrt{3}$

$\frac{5\sqrt{3}}{2}$

$5\sqrt{3}$

$\frac{2\sqrt{74}}{5}$

$\frac{2\sqrt{74}}{3}$

$\frac{3\sqrt{73}}{3}$

$2\sqrt{30}$