Bộ 10 Đề kiểm tra học kì I Chuyên đề toán 11: Kiểm tra 15 phút có đáp án (Đề 1)

$D=ℝ\backslash \left\{k2\pi ,k\in \mathbb{Z}\right\}$

$D=ℝ\backslash \left\{\pi +k2\pi ,k\in \mathbb{Z}\right\}$

$D=ℝ\backslash \left\{k\frac{\pi }{2},k\in \mathbb{Z}\right\}$

$D=ℝ\backslash \left\{1\right\}$

$T=3\pi$

$T=6\pi$

$T=9\pi$

$T=12\pi$

$\sin x=\sin \alpha \iff [\begin{array}{c}x=\alpha +k2\pi \\ x=-\alpha +k2\pi \end{array}$

$\cos x=\cos \alpha \iff [\begin{array}{c}x=\alpha +k2\pi \\ x=\pi -\alpha +k2\pi \end{array}$

$S=\left\{-\frac{\pi }{6}+k3\pi ,\frac{7\pi }{6}+k3\pi ,k\in \mathbb{Z}\right\}$

$S=\left\{-\frac{\pi }{6}+k\frac{\pi }{2},\frac{7\pi }{6}+k\frac{\pi }{2},k\in \mathbb{Z}\right\}$

$S=\left\{-\frac{\pi }{6}+k\pi ,\frac{7\pi }{6}+k\pi ,k\in \mathbb{Z}\right\}$

$S=\left\{-\frac{\pi }{6}+k2\pi ,\frac{7\pi }{6}+k2\pi ,k\in \mathbb{Z}\right\}$

$S=\left\{-\frac{\pi }{6}+k3\pi ,\frac{7\pi }{6}+k3\pi ,k\in \mathbb{Z}\right\}$

$S=\left\{-\frac{\pi }{6}+k\frac{\pi }{2},\frac{7\pi }{6}+k\frac{\pi }{2},k\in \mathbb{Z}\right\}$

$[\begin{array}{c}\cos x=-\frac{1}{2}\\ \cos x=-\frac{3}{2}\end{array}$

$[\begin{array}{c}\sin x=-\frac{1}{2}\\ \sin x=\frac{\sqrt{3}}{2}\end{array}$

$\sin x=-\frac{1}{2}$

$[\begin{array}{c}\cos x=\frac{2+\sqrt{11}}{2}\\ \cos x=\frac{2-\sqrt{11}}{2}\end{array}$

1

0

2

3

$m\in \left(-\infty ;-1\right)\cup \left(1;+\infty \right)$

$m\in \left[-1;1\right]$

$m\in \left(-\infty ;+\infty \right)$

$m\in \left(-\infty ;0\right)\cup \left(0;+\infty \right)$

3

2

0

1

$S=\left\{\frac{5\pi }{36}+\frac{k\pi }{2},\frac{11\pi }{36}+\frac{k\pi }{2},k\in \mathbb{Z}\right\}$

$S=\left\{\frac{5\pi }{36}+\frac{k\pi }{3},\frac{11\pi }{36}+\frac{k\pi }{3},k\in \mathbb{Z}\right\}$

$S=\left\{\frac{5\pi }{36}+\frac{k2\pi }{3},\frac{11\pi }{36}+\frac{k2\pi }{3},k\in \mathbb{Z}\right\}$

$S=\left\{\frac{5\pi }{36}+k2\pi ,\frac{11\pi }{36}+k2\pi ,k\in \mathbb{Z}\right\}$

S=5

S=4

S=6

$S=\frac{11}{2}$