Đề thi giữa kì 1 Toán 11 năm 2023-2024 THPT Lê Quý Đôn (TP.HCM) có đáp án

$\mathbb{R}.$

$\left[-1;1\right].$

$\mathbb{R}\backslash \left\{k\pi |k\in \mathbb{Z}\right\}.$

$\mathbb{R}\backslash \left\{\frac{\pi }{2}+k\pi |k\in \mathbb{Z}\right\}.$

$\cos 2a=1-2{\sin }^{2}a.$

$\cos 2a=1-2{\cos }^{2}a.$

$\cos 2a=2{\cos }^{2}a-1$

$\cos 2a={\cos }^{2}a-{\sin }^{2}a.$

$0,4142.$

$-0,4142.$

$1-\sqrt{2}.$

$\sqrt{2}-1.$

$\sin u+\sin v=2\sin \left(u+v\right)\cos \left(u-v\right).$

$\sin u+\sin v=2\sin \frac{u+v}{2}\sin \frac{u-v}{2}.$

$\sin u+\sin v=2\sin \frac{u+v}{2}\cos \frac{u-v}{2}.$

$\sin u+\sin v=2\cos \left(u+v\right)\sin \left(u-v\right).$

$$u_n=u_1+nd.$$

$$u_n=u_1+\left(n-1\right)d.$$

$$u_n=u_1-\left(n+1\right)d.$$

$$u_n=u_1+\left(n+1\right)d.$$

$$-150^0.$$

$$-30^0.$$

$$150^0.$$

$$30^0.$$

Dãy số $\left(u_n\right)$ không bị chặn trên và không bị chặn dưới.

Dãy số $\left(u_n\right)$ bị chặn dưới nhưng không bị chặn trên.

Dãy số $\left(u_n\right)$ bị chặn trên nhưng không bị chặn dưới.

Dãy số $\left(u_n\right)$ bị chặn.

$$\cos \left(a+b\right)=\sin a\cos b-\cos a\sin b.$$

$$\cos \left(a+b\right)=\cos a\cos b-\sin a\sin b.$$

$$\cos \left(a+b\right)=\sin a\cos b+\cos a\sin b.$$

$$\cos \left(a+b\right)=\cos a\cos b+\sin a\sin b.$$

$-1.$

$\frac{5}{2}.$

$-\frac{1}{7}.$

$5.$

$x=\sqrt{3}+k\pi \left(k\in \mathbb{Z}\right).$

$x=\frac{\pi }{3}+k\pi \left(k\in \mathbb{Z}\right).$

$x=\frac{\pi }{3}+k2\pi \left(k\in \mathbb{Z}\right).$

$x=\sqrt{3}+k2\pi \left(k\in \mathbb{Z}\right).$

$\sin \left(\pi -\alpha \right)=\sin \alpha .$

$\cos \left(\pi -\alpha \right)=\cos \alpha .$

$\tan \left(\pi -\alpha \right)=\tan \alpha .$

$\cot \left(\pi -\alpha \right)=\cot \alpha .$

$u_n=-2n+1.$

$1,3,5,7,9.$

$u_n=n+1.$

$1,4,2,6,9.$

$\cos \alpha =\frac{3}{5}.$

$\cos \alpha =-\frac{9}{25}.$

$\cos \alpha =-\frac{3}{5}.$

$\cos \alpha =\frac{9}{25}.$

$u_2=-\frac{3}{2}.$

$u_2=-6.$

$u_2=6.$

$u_2=-\frac{2}{3}.$

$$d=6.$$

$$d=-6.$$

$$d=4.$$

$$d=-4$$.

$y=\cos 2x$

$y=\cos x.$

$y=\sin x.$

$y=\sin 2x.$

$4.$

$6.$

$7.$

$10.$

$$x=k\pi \left(k\in \mathbb{Z}\right).$$

$$x=\pi +k2\pi \left(k\in \mathbb{Z}\right).$$

$$x=k2\pi \left(k\in \mathbb{Z}\right).$$

$$x=\frac{\pi }{2}+k\pi \left(k\in \mathbb{Z}\right).$$

$$y.$$

$$x.$$

$$\frac{y}{x}\left(x\ne 0\right).$$

$$\frac{x}{y}\left(y\ne 0\right).$$

$\left[-3;1\right].$

$\left[-1;1\right].$

$\left[-5;3\right].$

$\left(-1;1\right).$

$$x=\alpha +k\pi ,k\in \mathbb{Z}.$$

$$[\begin{array}{l}x=\alpha +k2\pi \\ x=\pi -\alpha +k2\pi \end{array},k\in \mathbb{Z}.$$

$$x=\alpha +2k\pi ,k\in \mathbb{Z}.$$

$$[\begin{array}{l}x=\alpha +k2\pi \\ x=-\alpha +k2\pi \end{array},k\in \mathbb{Z}.$$

$$1.$$

$$2.$$

$$3.$$

$$4.$$

$1,2,4,8.$

$1,2,4,6.$

$1,3,5,3.$

$9,7,5,3.$

$-1\le m\le 1.$

$m\ge -1.$

$-1<m<1.$

$m\le 1.$

$\frac{\pi }{4}.$

$\frac{\pi }{3}.$

$$\frac{\pi }{6}.$$

$$\frac{\pi }{2}.$$

$\frac{\pi }{8}cm.$

$\frac{\pi }{2}cm.$

$2\pi cm.$

$\pi cm.$

$$q=\frac{1}{2}.$$

$$q=-\frac{1}{2}.$$

$q=-2.$

$q=2.$

$\sin 4x+\sin 2x=2\sin 6x\cos 4x.$

$\sin 4x+\sin 2x=2\cos 6x\sin 2x.$

$\sin 4x+\sin 2x=2\sin 3x\cos x.$

$\sin 4x+\sin 2x=2\cos 3x\sin x.$

$[\begin{array}{l}x=15^0+k180^0\\ x=45^0+k180^0\end{array}\left(k\in \mathbb{Z}\right).$

$[\begin{array}{l}x=15^0+k360^0\\ x=45^0+k260^0\end{array}\left(k\in \mathbb{Z}\right).$

$[\begin{array}{l}x=60^0+k180^0\\ x=90^0+k180^0\end{array}\left(k\in \mathbb{Z}\right).$

$[\begin{array}{l}x=60^0+k360^0\\ x=90^0+k360^0\end{array}\left(k\in \mathbb{Z}\right).$

$5.$

$6.$

$7.$

$8.$

$u_1=1,d=4.$

$u_1=1,d=5.$

$u_1=3,d=6.$

$u_1=2,d=6.$

$u_n=3n+1.$

$u_n=3n-2.$

$u_n=n^2+1.$

$u_n=n^2.$

$u_3=12.$

$u_3=13.$

$u_3=11.$

$u_3=5.$

$u_{100}=-289.$

$u_{100}=-298.$

$u_{100}=-292.$

$u_{100}=-295.$

$u_n=2^{n-1}.$

$u_n=4n-2.$

$u_n=2n.$

$u_n=2^n.$