Đề thi giữa kì 1 Toán 11 THPT Chuyên Lê Khiết (Quảng Ngãi) năm 2023-2024 (có đáp án)

$y=\cot x$.

$y=\sin x$.

$y=\tan x$.

$y=\cos x$.

$-97$.

$503$.

$23$.

$103$.

$\{\begin{array}{l}{u}_1=-1\\ u_{n+1}=-3u_n,n\ge 1\end{array}$.

$\{\begin{array}{l}{u}_1=1\\ u_{n+1}=u_n+1,n\ge 1\end{array}$.

$\{\begin{array}{l}{u}_1=\frac{\pi }{2}\\ u_n=\sin \left(\frac{\pi }{n-1}\right),n\ge 1\end{array}$.

$\{\begin{array}{l}{u}_1=-2\\ u_{n+1}=2u_n+3,n\ge 1\end{array}$.

$\sin \left(a-b\right)=\sin a\cos a-\cos b\sin b$.

$\sin \left(a-b\right)=\sin a\cos b-\cos a\sin b$.

$\sin \left(a-b\right)=\sin a\cos a+\cos b\sin b$.

$\sin \left(a-b\right)=\sin a\cos b+\cos a\sin b$.

$m>1$.

$m<-1$.

$[\begin{array}{l}m<-1\\ m>1\end{array}$.

$-1\le m\le 1$.

$x=\pi +k\pi ,k\in \mathbb{Z}$.

$x=\pi +k2\pi ,k\in \mathbb{Z}$.

$x=-\frac{\pi }{2}+k2\pi ,k\in \mathbb{Z}$.

$x=\frac{3\pi }{2}+k\pi ,k\in \mathbb{Z}$.

$D=\mathbb{R}\backslash \left\{\frac{k\pi }{2}|k\in \mathbb{Z}\right\}$.

$D=\mathbb{R}\backslash \left\{\frac{\pi }{2}+k\pi |k\in \mathbb{Z}\right\}$.

$D=\mathbb{R}\backslash \left\{k2\pi |k\in \mathbb{Z}\right\}$.

$D=\mathbb{R}\backslash \left\{k\pi |k\in \mathbb{Z}\right\}$.

$\cot \alpha >0$.

$\tan \alpha >0$.

$\sin \alpha >0$.

$\cos \alpha >0$.

$10$.

$19$.

$9$.

$3$.

$u_2=1.$

$u_2=-5$.

$u_2=-1.$

$u_2=5$.

Cung có độ dài bằng đường kính của đường tròn đó.

Cung có độ dài bằng 1.

Cung tương ứng với góc ở tâm bằng $60^0$.

Cung có độ dài bằng bán kính của đường tròn đó.

$q=-\frac{1}{2}$.

$q=\frac{1}{2}$.

$q=2$.

$q=-2$.

$$\sin a.\sin b=-\frac{1}{2}\left[\sin \left(a+b\right)-\sin \left(a-b\right)\right]$$.

$$\sin a.\sin b=-\frac{1}{2}\left[\cos \left(a+b\right)-\cos \left(a-b\right)\right]$$.

$$\sin a.\sin b=\frac{1}{2}\left[\cos \left(a+b\right)-\cos \left(a-b\right)\right]$$.

$$\sin a.\sin b=\frac{1}{2}\left[\sin \left(a+b\right)-\sin \left(a-b\right)\right]$$.

Mốt.

Tứ phân vị.

Số trung vị.

Số trung bình.

$1;3;5;6;9$.

$10;8;6;4;2$.

$1;1;1;1;1$.

$1;5;3;7;9$.

$8$.

$9$.

$10$.

$5$.

$1,1,1,1$.

$1,0,-1,-2$.

$1,2,3,4$.

$1,2,4,8$.

$$x=\frac{\pi }{6}+k\pi ,k\in \mathbb{Z}$$.

$$x=\frac{\pi }{3}+k\pi ,k\in \mathbb{Z}$$.

Vô nghiệm.

$$x=\frac{\pi }{6}+k2\pi ,k\in \mathbb{Z}$$.

$u_n=n-2$.

$u_n=-n^2-6n$.

$u_n=1-2n$.

$u_n={\left(-1\right)}^n.n^2$.

$\sin \left(\frac{\pi }{2}-\alpha \right)=\sin \alpha$.

$\tan \left(\frac{\pi }{2}-\alpha \right)=\cot \alpha$.

$\sin \left(\frac{\pi }{2}-\alpha \right)=\cos \alpha$.

$\cos \left(\frac{\pi }{2}-\alpha \right)=\sin \alpha$.

$\left(w_n\right)$ với $w_n=\frac{n}{2^n}\left(\forall n\in {\mathbb{N}}^{\ast }\right)$.

$\left(v_n\right)$ với $v_n=\frac{n}{n+2}\left(\forall n\in {\mathbb{N}}^{\ast }\right)$.

$\left(u_n\right)$ với $u_n=\frac{n-1}{2^n}\left(\forall n\in {\mathbb{N}}^{\ast }\right)$.

$\left(t_n\right)$ với $t_n=\frac{1}{n+1}\left(\forall n\in N^{\ast }\right)$.

$$5,92$$.

$$7,68$$.

$$6,65$$.

$$5,64$$.

$\left(-\pi ;0\right)$.

$\left(0;\pi \right)$.

$\left(\frac{\pi }{2};\pi \right)$.

$\left(-\frac{\pi }{2};\frac{\pi }{2}\right)$.

$P=4$.

$P=\frac{8}{5}$.

$P=3$.

$P=\frac{3}{5}$.

$M>0$.

$M\le 0$.

$M\ge 0$.

$M<0$.

$x=64$.

$x=24$.

$x=32$.

$x=16$.

$u_n=3^{n-1}.$

$u_n=3^n.$

$u_n=3^{n+1}.$

$u_n=3+3^n.$

$u_1=2;d=-\frac{1}{2}$.

$u_1=-\frac{3}{2};d=-2$.

$u_1=-4;d=\frac{3}{2}$.

$u_1=\frac{5}{2};d=\frac{1}{2}$.

$$S=\frac{\pi }{2}$$.

$$S=\frac{\pi }{6}$$.

$$S=\frac{\pi }{3}$$.

$$S=\frac{5\pi }{6}$$.

$M=\cos 4b$.

$M=\sin 2b$.

$M=\cos 2b$.

$M=\sin 4b$.

$-\frac{\sqrt{5}}{3}$.

$-\frac{\sqrt{5}}{2}$.

$\frac{\sqrt{5}}{2}$.

$\frac{\sqrt{5}}{3}$.

$m=-1$.

$m=-2023\sqrt{2}$.

$m=-\sqrt{2}$.

$m=-2024\sqrt{2}$.

$76$ ngày.

$90$ ngày.

$80$ ngày.

$66$ ngày.

$14$.

$28$.

$10$.

$8$.

33.

20.

34.

35.