ĐGTD ĐH Bách khoa - Tư duy Toán học - Góc giữa hai mặt phẳng trong không gian

$a\sqrt{2}.$

$a\sqrt{3}.$

2a.

a.

$\phi ={30}^0.$

$\sin \phi =\frac{\sqrt{5}}{5}.$

$\phi ={60}^0.$

$\sin \phi =\frac{2\sqrt{5}}{5}.$

${30}^0.$

${45}^0.$

${60}^0.$

${90}^0.$

2a.

$2a\sqrt{3}.$

$a\sqrt{3}.$

$a\sqrt{2}.$

$\phi ={60}^0.$

$\tan \phi =2\sqrt{3}.$

$\tan \phi =\frac{\sqrt{3}}{6}.$

$\tan \phi =\frac{1}{2}.$

2a.

3a.

$a\sqrt{3}.$

$a\sqrt{2}.$

$\phi ={90}^0.$

$\phi ={60}^0.$

$\phi ={45}^0.$

$\phi ={30}^0.$

$\tan \phi =\sqrt{5}.$

$\tan \phi =\frac{\sqrt{5}}{5}.$

$\tan \phi =\frac{\sqrt{3}}{2}.$

$\phi ={45}^0.$

$\tan \phi =\frac{\sqrt{2}}{3}.$

$\tan \phi =\frac{2\sqrt{3}}{3}.$

$\tan \phi =\frac{\sqrt{3}}{3}.$

$\tan \phi =\frac{\sqrt{3}}{2}.$

$\widehat{CSF}.$

$\widehat{BSF}.$

$\widehat{BSE}.$

$\widehat{CSE}.$

$\tan \phi =\sqrt{6}.$

$\tan \phi =\frac{\sqrt{2}}{2}.$

$\tan \phi =\frac{\sqrt{3}}{2}.$

$\tan \phi =\sqrt{2}.$

$SH=\frac{a\sqrt{3}}{2}.$

$SH=\frac{a\sqrt{2}}{3}.$

$SH=\frac{a}{2}.$

$\tan \phi =\frac{\sqrt{2}}{2}.$

$\phi ={45}^0.$

$\phi ={60}^0.$

$\phi ={30}^0.$

$\frac{a\sqrt{3}}{2}.$

$\frac{a}{2\sqrt{3}}.$

$\frac{a\sqrt{3}}{3}.$

$\frac{a\sqrt{2}}{3}.$

$\cot \phi =\frac{\sqrt{2}}{4}.$

$\cot \phi =\sqrt{7}.$

$\cot \phi =\frac{\sqrt{7}}{7}.$

$\cot \phi =\frac{\sqrt{14}}{4}.$

$\frac{R}{\sqrt{2}}.$

$\frac{R}{2}.$

$\frac{R}{4}.$

$\frac{R}{2\sqrt{2}}.$

${30}^0.$

${45}^0.$

${60}^0.$

${90}^0.$

$\frac{a\sqrt{3}}{3}.$

$\frac{a}{2}.$

$\frac{a\sqrt{2}}{2}.$

$\frac{a}{3}.$

$\frac{3}{2\sqrt{15}}$

$\frac{1}{\sqrt{15}}$

$\frac{\sqrt{14}}{\sqrt{15}}$

$\frac{\sqrt{14}}{3\sqrt{15}}$

$\cos \alpha =\frac{1}{3}.$

$\cos \alpha =\frac{\sqrt{2}}{3}.$

$\cos \alpha =\frac{\sqrt{3}}{3}.$

$\cos \alpha =\frac{2}{3}.$