Top 10 đề thi Đánh giá năng lực ĐHQG Hà Nội năm 2023 - 2024 có đáp án (Đề 5)

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t = 2

t =1

t = 3

t = 4

$x=\frac{8}{3}$

$x=\frac{10}{3}$

$x=\frac{16}{3}$

$x=\frac{11}{3}$

$x=4$

$x=\frac{5}{2}$

$x=\frac{7}{2}$

$x=2$

1

2

3

4

$\left(P\right):6x+3y+2z+18=0$

$\left(P\right):6x+3y+2z+6=0$

$\left(P\right):6x+3y+2z-18=0$

$\left(P\right):6x+3y+2z-6=0$

$I\left(4;0;-2\right).$

$I\left(2;0;-1\right).$

$I\left(2;0;-4\right).$

$I\left(2;-2;-1\right).$

$\left(-\frac{1}{2};\frac{1}{2}\right).$

$\left[-\frac{1}{2};\frac{1}{2}\right)\cup \left(1;+\infty \right)$

$\left[-\frac{1}{2};\frac{1}{2}\right].$

$\left(-\infty ;-\frac{1}{2}\right]\cup \left(\frac{1}{2};1\right).$

$[\begin{array}{l}x=\frac{\pi }{18}+k\frac{\pi }{2}\\ x=\frac{\pi }{9}+k\frac{\pi }{3}\end{array}$

$[\begin{array}{l}x=\frac{\pi }{12}+k\frac{\pi }{2}\\ x=\frac{\pi }{24}+k\frac{\pi }{3}\end{array}$

$[\begin{array}{l}x=\frac{\pi }{16}+k\frac{\pi }{2}\\ x=\frac{\pi }{8}+k\frac{\pi }{3}\end{array}$

$[\begin{array}{l}x=\frac{\pi }{4}+k\frac{\pi }{2}\\ x=\frac{\pi }{6}+k\frac{\pi }{3}\end{array}$

$6m^2$

$8m^2$

$10m^2$

$12m^2$

$F\left(x\right)=\frac{\ln |2x+3|}{2}+1$.

$F\left(x\right)=\frac{\ln {|2x+3|}^2}{4}+3$.

$F\left(x\right)=\frac{\ln |4x+6|}{4}+2$.

$F\left(x\right)=\frac{\ln |x+\frac{3}{2}|}{2}+4$.

$m\le f\left(2\right)$.

$m<f\left(1\right)-1$.

$m\ge f\left(2\right)-1$.

$m\ge f\left(1\right)+1$.

$20m$

$80m$

$60m$

$40m$

2042

2041

2039

2040

$\left(-\frac{1}{3};1\right)$

$\left(-\infty ;\frac{6}{7}\right)$

$\left(-\frac{1}{3};\frac{6}{7}\right)$

$\left(\frac{6}{7};1\right)$

V = 4.

V = 9.

$V=4\pi$.

$V=9\pi$.

$\left(-\infty ;7\right].$

$\left(-\infty ;6\right].$

$\left[5;+\infty \right).$

$\left(-\infty ;5\right].$

$2\sqrt{2}$.

$\sqrt{5}$.

$\sqrt{10}$.

$2\sqrt{5}$.

Đường tròn${\left(x+2\right)}^2+{\left(y-1\right)}^2=4$.

Đường tròn tâm $I\left(2;-1\right)$ và bán kính $R=2$

Đường thẳng $x-y-2=0$.

Đường thẳng $x+y-2=0$.

$[\begin{array}{l}m=0\\ m=-10\end{array}$

$[\begin{array}{l}m=10\\ m=-10\end{array}$

$[\begin{array}{l}m=0\\ m=-20\end{array}$

$[\begin{array}{l}m=10\\ m=-20\end{array}$

${\left(x+3\right)}^2+{\left(y-1\right)}^2=\sqrt{5}$

${\left(x-3\right)}^2+{\left(y+1\right)}^2=\sqrt{5}$

${\left(x+3\right)}^2+{\left(y-1\right)}^2=5$

$a+b+c=-12$

$a+b+c=6$

$a+b+c=12$

$a+b+c=-9$

$\frac{3\pi a^2}{4}$

$\pi a^2$

$2\pi a^2$

$\frac{\pi a^2}{2}$

10 lần.

24 lần

12 lần.

20 lần.

$\frac{a^3\sqrt{3}}{3}.$

$\frac{3a^2}{16}.$

$\frac{2a^3\sqrt{3}}{3}.$

$\frac{a^3}{16}.$

$d\left(AM;BC\right)=\frac{\sqrt{3}}{2}$

$d\left(AM;BC\right)=\frac{2\sqrt{3}}{3}$

$$d\left(AM;BC\right)=\frac{3\sqrt{22}}{11}$$

$d\left(AM;BC\right)=\frac{\sqrt{22}}{6}$

$\sqrt{34}$

$\sqrt{26}$

$34$

$26$

$\frac{x+3}{2}=\frac{y+1}{-1}=\frac{z-1}{2}$

$\frac{x-2}{3}=\frac{y+1}{1}=\frac{z-2}{-1}$

$\frac{x-3}{2}=\frac{y-1}{1}=\frac{z+1}{2}$

$\frac{x-3}{2}=\frac{y-1}{-1}=\frac{z+1}{2}$

3.

0.

1.

2.

$4$

$4\sqrt{2}$

$\sqrt{6}$

$2\sqrt{6}$

5

2

1

3

$3-\sqrt{3}$

$2-\sqrt{3}$

$-\sqrt{3}$

$\sqrt{3}$

10

-3

13

3