Top 10 đề thi Đánh giá năng lực ĐHQG Hà Nội năm 2023 - 2024 có đáp án (Đề 1)

Táo

Trứng

Thịt lợn

Thịt bò

12(m/s).

6(m/s).

2(m/s).

16(m/s).

$x=\frac{7}{2}.$

$x=8.$

$x=3.$

$x=5.$

1

2

3

Vô nghiệm

$z=3-2i$

$z=-2-3i$

$z=2+3i$

$z=-2+i$

$\frac{x}{1}-\frac{y}{2}+\frac{z}{3}=1$

$\frac{x}{1}+\frac{y}{2}-\frac{z}{3}=1$

$\frac{x}{1}-\frac{y}{2}-\frac{z}{3}=1$

$\frac{x}{1}+\frac{y}{2}+\frac{z}{3}=1$

$120^0$

$90^0$

$30^0$

$60^0$

3

4

5

6

1

4

2

3

250500.

12550.

25250.

125250.

$f\left(x\right)=\frac{\sin x}{{\left(2+\cos x\right)}^2}+C$

$f\left(x\right)=-\frac{1}{2+\sin x}+C$

$f\left(x\right)=\frac{\sin x}{2+\sin x}+C$

$f\left(x\right)=\frac{1}{2+\cos x}+C$

$m\le 3f\left(\sqrt{3}\right)$

$m\le 3f\left(0\right)$

$m\ge 3f\left(1\right)$

$m\ge 3f\left(-\sqrt{3}\right)$

125m.

75m.

200m.

100m.

6%/năm.

5%/năm.

8%/năm.

7%/năm.

$\left(-\infty ;2\right)$

$\left(-\infty ;2\right]$

$(0;2]$

$\left(-\infty ;0\right)\cup \left(0;2\right]$

$\underset{0}{\overset{2}{\int }}\left|x^2-2x\right|dx$

$\pi \underset{0}{\overset{2}{\int }}\left|x^2-2x\right|dx$

$\pi \underset{0}{\overset{2}{\int }}{\left(x^2-2x\right)}^{2}dx$

$\underset{0}{\overset{2}{\int }}{\left(x^2-2x\right)}^{2}dx$

$m\le -3$

$m\ge 0$

$m\ge -3$

$m\le 0$

-9.

9

13.

$-13$.

$R=\frac{\sqrt{10}}{3}$

$R=\frac{10}{9}$

$R=2\sqrt{3}$

$R=\frac{7}{3}$

$\frac{3}{2}$

$\frac{9}{2}$

$\frac{27}{2}$

13

$m=-\frac{1}{3}$

$m=3$

$m=\frac{1}{3}$

$m=-3$

$5x+2y-z+14=0$

$x-4y-3z+6=0$

$x-4y-3z-6=0$

$5x+2y-z+4=0$

$\pi a^2$

$\pi a^2\sqrt{2}$

$\frac{\pi a^2\sqrt{2}}{2}$

$\frac{\pi a^2\sqrt{2}}{4}$

3

9

$\frac{1}{3}$

$\frac{1}{9}$

$$\frac{3a^3}{8}$$

$$\frac{a^3\sqrt{3}}{2}$$

$$\frac{a^3}{8}$$

$$\frac{a^3\sqrt{3}}{4}$$

$\frac{GI}{GA}=\frac{1}{4}$

$\frac{GI}{GA}=\frac{1}{5}$

$\frac{GI}{GA}=\frac{1}{2}$

$\frac{GI}{GA}=\frac{1}{3}$

3

5

$\sqrt{3}$

$\sqrt{23}$

$\frac{x+3}{2}=\frac{y-1}{1}=\frac{z-2}{-1}$

$\frac{x-1}{-2}=\frac{y+1}{-1}=\frac{z}{1}$

$\frac{x-1}{2}=\frac{y+1}{-1}=\frac{z}{-1}$

$\frac{x+3}{2}=\frac{y-1}{-1}=\frac{z-2}{-1}$

$\left(-3;4\right)$

$\left(3;2\right)$

$\left(5;8\right)$

$\left(5;4\right)$

$M\left(-1;2;0\right)$

$M\left(-1;-2;0\right)$

$M\left(1;-2;0\right)$

$M\left(1;2;0\right)$

2

1

3

5

$m=9$

$m\in \left[9;10\right]$

$$m\in \left(9;10\right)$$

$$m=10$$

$\frac{37}{6}$

$\frac{527}{3}$

$\frac{61}{6}$

$\frac{464}{3}$

$\frac{5}{6}$

$\frac{1}{2}$

$\frac{3}{4}$

$\frac{49}{198}$

$$V_1=\frac{7a^3}{12}$$

$$V_1=\frac{95a^3}{216}$$

$$V_1=\frac{25a^3}{72}$$

$$V_1=\frac{181a^3}{432}$$