Đề thi Đánh giá năng lực ĐHQG Hà Nội năm 2024 - 2025 có đáp án (Đề 23)

Năm 2018.

Năm 2021.

Năm 2022.

Năm 2023.

$t=3$.

$t=4$.

$t=1$.

$t=2$.

0 .

1 .

2 .

3 .

$a>\frac{1}{2}$.

$a>\frac{1}{3}$.

$a>-\frac{1}{2}$.

$a<\frac{1}{2}$.

$\mathrm{Q}\left(5;-12\right)$.

$$\mathrm{N}\left(13;-12\right)$$.

$\mathrm{M}\left(13;12\right)$

$\mathrm{P}\left(5;12\right)$.

$x-2y-2z=0$.

$x-2y-z-1=0$.

$x-2y-z=0$.

$x-2y+z-3=0$

$\mathrm{M}{\mathrm{M}}^{\prime }=2\sqrt{17}$.

$\mathrm{M}{\mathrm{M}}^{\prime }=2\sqrt{65}$.

$M{\mathrm{M}}^{\prime }=8$.

$\mathrm{M}{\mathrm{M}}^{\prime }=10\sqrt{2}$.

5 .

6 .

21.

40.

$\frac{7\pi }{2}$.

$\pi$.

$\frac{3\pi }{2}$.

$\frac{\pi }{4}$.

$-59048$.

$-59049$.

$-155$.

$-310$.

$y=\ln \left|1-x\right|$.

$y=-\ln \left|1-x\right|$.

$y=\ln \frac{1}{x-1}$.

$y=\ln \left|x-1\right|$.

$m>f\left(0\right)$.

$\mathrm{m}>\mathrm{f}\left(2\right)-4$.

$\mathrm{m}\ge \mathrm{f}\left(0\right)$.

$m\ge f\left(2\right)-4$.

$v=3\ln 3$.

$v=14$

$v=3\ln 3+6$.

$v=26$.

2 .

3 .

5 .

4 .

0 .

1 .

Vô số.

2 .

$V=\frac{4\pi }{3}$.

$V=2\pi$.

$\mathrm{V}=\frac{4}{3}$.

$\mathrm{V}=2$.

3.

2

4.

5.

10.

12.

$2\sqrt{34}$.

$4\sqrt{5}$.

$\mathrm{I}\left(-4;-3\right)$.

$\mathrm{I}\left(4;3\right)$.

$I\left(3;4\right)$.

$I\left(-3;-4\right)$.

$\left(3;-3\right)$.

$\left(-3;3\right)$.

$$\left(-3;-3\right)$$.

$\left(-2;-3\right)$.

$7x+y-2=0$

$7x-y=0$.

$x-7y-2=0$.

$x+7y-2=0$.

$\left(\mathrm{Q}\right):x-2y-z-5=0$.

$\left(\mathrm{Q}\right):x-2y-z+7=0$.

$\left(\mathrm{Q}\right):x-2y-z-7=0$.

$\left(\mathrm{Q}\right):x-2y-z+5=0$.

$\frac{\pi \mathrm{a}\sqrt{2}}{4}$.

$\frac{\pi {\mathrm{a}}^3\sqrt{2}}{6}$.

$\frac{\pi {\mathrm{a}}^2\sqrt{2}}{12}$.

$\frac{\pi {\mathrm{a}}^3\sqrt{2}}{12}$.

$9\pi +9x$.

$18\pi +18$.

36.

$27\pi$.

$\frac{a^3\sqrt{3}}{6}$.

$\frac{a^3\sqrt{3}}{12}$.

$\frac{a^3\sqrt{3}}{24}$

$\frac{a^3\sqrt{3}}{36}$.

$\frac{1}{2}$.

$\frac{1}{3}$.

2 .

3 .

$\mathrm{M}\left(-\frac{11}{3};\frac{14}{3};\frac{13}{3}\right)$.

$\mathrm{M}\left(\frac{29}{3};-\frac{26}{3};-\frac{7}{3}\right)$.

$\mathrm{M}\left(-\frac{29}{3};\frac{26}{3};-\frac{7}{3}\right)$.

$M\left(\frac{11}{3};\frac{14}{3};-\frac{13}{3}\right)$.

$\{\begin{array}{l}x=-1+t\\ y=-2-2t\\ z=2+3t\end{array}$.

$\{\begin{array}{l}x=1+t\\ y=2-2t\\ z=-2+3t\end{array}$.

$\{\begin{array}{l}x=-1+t\\ y=-2-2t\\ z=2\end{array}$.

$\{\begin{array}{l}x=1+t\\ y=2-2t\\ z=-2\end{array}$.

2.

1.

4.

3.

$16x+40y-44z+39=0$.

$16x+40y+44z-39=0$.

$16x-40y-44z+39=0$.

$16x-40y-44z-39=0$.