Đề thi Đánh giá năng lực ĐHQG Hà Nội năm 2024 - 2025 có đáp án (Đề 21)

Ấn Độ.

Trung Quốc.

Thổ Nhĩ Kỳ.

Mỹ.

$-\frac{8}{27}.$

$\frac{2}{9}$.

$\frac{8}{27}.$

$-\frac{4}{27}.$

2.

$\frac{17}{2}.$

8.

$-2.$

3.

1.

4.

2.

$z=\left(1+i\right)\left(2-i\right).$

$$z=\left(1+i\right)\left(2-3i\right).$$

$z=\frac{3-2i}{i}.$

$z=\frac{i}{2+3i}.$

$\left(Q\right):3x-2y+4z-4=0.$

$\left(Q\right):3x-2y+4z+4=0.$

$\left(Q\right):3x-2y+4z+5=0.$

$\left(Q\right):3x+2y+4z+8=0.$

1.

2.

3.

4.

$A^{\prime }\left(3;-2;1\right).$

$A^{\prime }\left(3;2;-1\right).$

$A^{\prime }\left(3;-2;-1\right).$

$A^{\prime }\left(1;2;0\right).$

5.

4.

2.

3.

$$15580000$$ đồng.

$$18500000$$ đồng.

$$15850000$$ đồng.

$$15050000$$ đồng.

$a+2b=8.$

$a+b=8.$

$2a-b=8.$

$a-b=8.$

$m\in \left(-4;5\right).$

$m\in \left(-5;4\right).$

$m\le -5$ hoặc $m\ge 4.$

$m<-4$ hoặc $m>5.$

$30\pi \mathrm{c}{\mathrm{m}}^3.$

$72\pi \mathrm{c}{\mathrm{m}}^3.$

$48\pi \mathrm{c}{\mathrm{m}}^3.$

$54\pi \mathrm{c}{\mathrm{m}}^3.$

8.

9.

7.

10.

420.

410.

400.

390.

$\pi .$

$\pi -1.$

$3\pi .$

$2\pi .$

55.

35.

40.

45.

$T=10.$

$T=5+2\sqrt{7}.$

$T=5+\sqrt{7}.$

$T=\sqrt{38}+2\sqrt{7}.$

$B\left(0;-1\right).$

$B\left(-1;0\right).$

$B\left(0;3\right).$

$B\left(3;0\right).$

$$-36.$$

12.

$$-56.$$

486.

Trục $$Oy.$$

Trục $$Ox.$$

Đường thẳng $y=x.$

Đường thẳng $y=-x.$

$6x+3y+2z-24=0.$

$6x+3y+2z-12=0.$

$6x+3y+2z=0.$

$6x+3y+2z-36=0.$

$3\sqrt{2}\pi a^2.$

$3\pi a^2.$

$\sqrt{3}\pi a^2.$

$2\pi a^2.$

3.

4.

5.

2.

$\frac{4\sqrt{2}}{3}.$

$4\sqrt{3}.$

$\frac{4\sqrt{3}}{3}.$

$4\sqrt{2}.$

$\left(m;n\right)=\left(1;2\right).$

$\left(m;n\right)=\left(1;0\right).$

$\left(m;n\right)=\left(2;0\right).$

$\left(m;n\right)=\left(0;2\right).$

$10\mathrm{m}.$

$6\mathrm{m}.$

$12\mathrm{m}.$

$8\mathrm{m}.$

$\frac{6\sqrt{210}}{35}.$

$\frac{\sqrt{210}}{35}.$

$\frac{2\sqrt{210}}{35}.$

$\frac{3\sqrt{210}}{35}.$

$\{\begin{array}{l}x=3+t\\ y=1-t\\ z=1+t\end{array}$.

$\{\begin{array}{l}x=-1+t\\ y=4-2t\\ z=-3+3t\end{array}$.

$\{\begin{array}{l}x=3+3t\\ y=1-t\\ z=1+t\end{array}$.

$\{\begin{array}{l}x=-3+3t\\ y=5-2t\\ z=-1+t\end{array}$.

$$\left(\frac{29}{13};\frac{58}{13};\frac{5}{13}\right).$$

$\left(4;3;1\right).$

$$\left(1;3;4\right).$$

$\left(\frac{37}{3};-\frac{56}{3};\frac{68}{3}\right).$

3.

Vô số.

5.

4.

1.

2.

3.

4.

$I=1.$

$I=e.$

$I=\frac{1+e}{2}.$

$I=e-1.$