Đề thi Đánh giá năng lực ĐHQG Hồ Chí Minh năm 2025 có đáp án (Đề 21) – Phần 2

Misinformation.

Damaged reputations.

Political activism.

Incorrect public opinion.

something large.

something influential.

something affected.

something debated.

people.

social platforms.

news channels.

voices.

Social media is increasingly used to promote commercial products.

Online platforms play a major role in shaping news and public opinion.

News platforms rely on social media to communicate with their audience.

Social media platforms prevent the spread of misinformation effectively.

Social media companies are fully successful in stopping misinformation.

Most people do not trust information shared on social media.

Social media has a strong influence on public discourse and activism.

The spread of information on social media is limited to personal updates.

Social media remains the most popular tool for global communication.

The way people communicate on social media is constantly changing.

Social media has finally reached its peak in communication.

There is little change in how social media affects communication.

Social media has replaced traditional news channels completely.

People need to be cautious when trusting information on social media.

Social media limits opportunities for social interaction.

Fact-checking prevents all misinformation on social platforms.

0,236.

0,632.

0,362.

0,263.

$\left[0;6\right]$.

$\left(0;6\right)\cap \left(-\infty ;-1\right)$.

$\left(0;6\right)$.

$\left[0;6\right]\cap \left(-\infty ;-1\right)$.

$a=-1;b=0$.

$a=-1;b=1$.

$a=1;b=0$.

$a=1;b=2$.

$x^4+\frac{1}{\sqrt{x}}-\frac{3}{x^2}$.

$x^4-\frac{1}{\sqrt{x}}-\frac{3}{x^2}$.

$x^4+\frac{1}{\sqrt{x}}+\frac{3}{x^2}$.

$-x^4+\frac{1}{\sqrt{x}}-\frac{3}{x^2}$.

Hàm số đã cho đồng biến trên $\mathbb{R}$.

Hàm số đã cho nghịch biến trên khoảng $\left(-1;10\right)$.

Hàm số đã cho nghịch biến trên khoảng $\left(0;10\right)$.

Hàm số đã cho nghịch biến trên khoảng $\left(-10;0\right)$.

$0$.

$1$.

$2$.

$3$.

$\left(-\infty ;2\right)$.

$\left(0;2\right)$.

$\left(2;+\infty \right)$.

$\left(-\infty ;-2\right)$.

$x=2$.

$x=-2$.

$x=0$.

$x=1$.

$0$.

$1$.

$2$.

$3$.

$d=-1$.

$d=0$.

$d=-2$.

$d=3$.

$\frac{10}{3}$.

$-\frac{11}{2}$.

$-\frac{1}{3}$.

$\frac{2}{3}$.

$C\left(n\right)=100{\left(1+0,12\right)}^n$.

$C\left(n\right)=100{\left(1-0,12\right)}^n$.

$C\left(n\right)=10{\left(1+0,12\right)}^n$.

$C\left(n\right)=100{\left(1+0,012\right)}^n$.

4.

5.

3.

2.

$\{\begin{array}{l}x=t\\ y=4-t\end{array}\left(t\in \mathbb{R}\right)$.

$\{\begin{array}{l}x=1\\ y=-1+4t\end{array}\left(t\in \mathbb{R}\right)$.

$\{\begin{array}{l}x=t\\ y=4+t\end{array}\left(t\in \mathbb{R}\right)$.

$\{\begin{array}{l}x=1\\ y=1+4t\end{array}\left(t\in \mathbb{R}\right)$.

$\left(0;1\right)$.

$\left(0;-1\right)$.

$\left(0;4\right)$.

$\left(5;4\right)$.

$S=\left\{3^{\sqrt{3}}\right\}$.

$S=\left\{3^{-\sqrt{3}}\right\}$.

$S=\left\{3^{-\sqrt{3}};3^{\sqrt{3}}\right\}$.

$S=\left\{-3;2\right\}$.

$0<m<2$.

$m\le 0$.

$m\ge 2$.

$0\le m\le 2$.

$8,3$.

$7,5$.

$8,5$.

$8$.

$0,3667$.

$0,3666$.

$0,3663$.

$0,3665$.

$\frac{1}{4}$.

$\frac{3}{4}$.

$\frac{9}{14}$.

$\frac{5}{14}$.

9.

10.

11.

12.

$13$.

$20$.

$-21$.

$-14$.

$h\left(t\right)=-\frac{1}{40}{t}^4+\frac{11}{30}{t}^3+20$.

$h\left(t\right)=-\frac{1}{40}{t}^4+\frac{11}{30}{t}^3$.

$h\left(t\right)=\frac{1}{40}{t}^4-\frac{11}{30}{t}^3+20$.

$h\left(t\right)=\frac{1}{40}{t}^4-\frac{11}{30}{t}^3$.