Đề thi giữa kì 1 Toán 11 Chân trời sáng tạo (2023-2024) – Đề 11 (có đáp án)

$$9^0.$$

$20^0.$

$5^0.$

$10^0.$

$\frac{5}{13}.$

$-\frac{5}{13}.$

$\frac{1}{13}.$

$-\frac{1}{13}.$

$\cos 2\alpha =2\sin \alpha \cos \alpha .$

$\cos 2\alpha =2{\cos }^2\alpha -1.$

$\cos 2\alpha =1-2{\sin }^2\alpha .$

$\cos 2\alpha ={\cos }^2\alpha -{\sin }^2\alpha .$

$\frac{7}{9}.$

$-\frac{3}{11}.$

$-\frac{3}{7}.$

$\frac{9}{7}.$

$$A=\tan \alpha .$$

$$A=\tan 2\alpha .$$

$$A=\cot \alpha .$$

$$A=\cot 2\alpha .$$

$$x\ne k\pi (k\in \mathbb{Z})$$.

$$x\ne \frac{\pi }{6}+\frac{k\pi }{3}(k\in \mathbb{Z})$$.

$$x\ne \frac{k\pi }{3}(k\in \mathbb{Z})$$.

$$x\ne \frac{k2\pi }{3}(k\in \mathbb{Z})$$.

$$M=2,m=1.$$

$$M=2,m=-1.$$

$$M=-1,m=-2.$$

$$M=1,m=-2.$$

$\left(-\sqrt{2};-\frac{\sqrt{3}}{2}\right).$

$\left(-\frac{1}{2};0\right).$

$\left(-1;-\frac{1}{2}\right).$

$\left(-\frac{1}{2};\frac{1}{2}\right).$

$x=\frac{\pi }{2}+k2\pi \left(k\in \mathbb{Z}\right).$

$x=\frac{\pi }{2}+k\pi \left(k\in \mathbb{Z}\right).$

$x=\pi +k2\pi \left(k\in \mathbb{Z}\right).$

$x=k2\pi \left(k\in \mathbb{Z}\right).$

$x=\frac{\pi }{2}+k\pi \left(k\in \mathbb{Z}\right).$

$x=\frac{\pi }{4}+k\pi \left(k\in \mathbb{Z}\right).$

$x=\frac{\pi }{4}+\frac{k\pi }{2}\left(k\in \mathbb{Z}\right).$

$x=k\pi \left(k\in \mathbb{Z}\right).$

$x=\frac{\pi }{6}+k\pi \left(k\in \mathbb{Z}\right).$

$x=\frac{5\pi }{12}+k\pi \left(k\in \mathbb{Z}\right).$

$x=\frac{5\pi }{12}+k2\pi \left(k\in \mathbb{Z}\right).$

$x=\frac{\pi }{6}+k2\pi \left(k\in \mathbb{Z}\right).$

$2n$.

$2n+2$.

$2n+1$.

$n+1$.

$u_n=2n^2+3$.

$u_n=2n+3$.

$u_n=\frac{n+7}{n+6}$.

$u_n=\sin n$.

$M\in (P).$

$M\in a.$

$a\in (P).$

$b\subset (P).$

$SD.$

$SO.$

$SB.$

$SA.$

$$MN//AB.$$

$$MN//BC.$$

$$MN//AC.$$

$$MN//DB.$$

Đường thẳng $$Kx$$, với $$Kx$$ song song với $$BD$$.

Đường thẳng $$Kx$$, với $$Kx$$ song song với $$AC$$.

Đường thẳng $$Kx$$, với $$Kx$$ song song với $$CD$$.

Đường thẳng $$Kx$$, với $$Kx$$ song song với $$BC$$.

$I=AM\cap SO$.

$I=AM\cap SD$.

$I=AM\cap BD.$

$I=AM\cap SB$.

$$SA$$ và $$BC$$ chéo nhau.

$$SB$$ và $$BD$$ cắt nhau.

$$SA$$ và $$BC$$ cắt nhau.

$$AD$$ và $$BC$$ song song.

$\left(ABC\right)$.

$\left(ABD\right)$.

$\left(BCD\right)$.

$\left(ACD\right)$.