220 câu trắc nghiệm tổng hợp Toán cao cấp A2 có đáp án - Phần 8

(0;4;1)

(0;-1;4)

(1;0;0),(0;-1,4)

(1;0;0),(0;-1,-2)

$$\mathrm{V}=\left\{({\mathrm{x}}_1,{\mathrm{x}}_2,{\mathrm{x}}_3)/{\mathrm{x}}_1={\mathrm{x}}_2={\mathrm{x}}_3=0\right\}$$

$$\mathrm{V}=\left\{({\mathrm{x}}_1,{\mathrm{x}}_2,{\mathrm{x}}_3)/{\mathrm{x}}_1=0,{\mathrm{x}}_2=-{\mathrm{x}}_3,{\mathrm{x}}_3\in \mathrm{R}\right\}$$

$$\mathrm{V}=\left\{({\mathrm{x}}_1,{\mathrm{x}}_2,{\mathrm{x}}_3)/{\mathrm{x}}_1=3{\mathrm{x}}_3,{\mathrm{x}}_2=3{\mathrm{x}}_3,{\mathrm{x}}_3\in \mathrm{R}\right\}$$

$$\mathrm{V}=\left\{({\mathrm{x}}_1,{\mathrm{x}}_2,{\mathrm{x}}_3)/{\mathrm{x}}_1=3{\mathrm{x}}_3+1,{\mathrm{x}}_2=3{\mathrm{x}}_3,{\mathrm{x}}_3\in \mathrm{R}\right\}$$

$$\mathrm{A}=\left(\begin{array}{ccc}1& -2& -1\\ -2& 0& 0\\ -1& 0& 0\end{array}\right)$$

$$\mathrm{A}=\left(\begin{array}{ccc}1& -1& \frac{-1}{2}\\ -1& 0& 0\\ \frac{-1}{2}& 0& 0\end{array}\right)$$

$$\mathrm{A}=\left(\begin{array}{ccc}\frac{1}{2}& -1& \frac{-1}{2}\\ -1& 0& 0\\ \frac{-1}{2}& 0& 0\end{array}\right)$$

$$f\left(x_1,x_2,x_3\right)=2{x_1}^2+2{x_2}^2-5{x_3}^2-6x_1{x}_2$$

$$f\left(x_1,x_2,x_3\right)=2{x_1}^2+2{x_2}^2-5{x_3}^2-3x_1{x}_2$$

$$f\left(x_1,x_2,x_3\right)={x_1}^2+2{x_2}^2-\frac{5}{2}{x_3}^2-3x_1{x}_2$$

Một đáp án khác

m > 25

$$\mathrm{m}\le 25$$

m = 25

Không có giá trị m

m > 2

$$\mathrm{m}\le 2$$

m = 2

$$\forall \mathrm{m}\in \mathrm{R}$$

y = -x - 1

y = x + 1

y = 1 - x

y = x - 1

Phương trình có nghiệm duy nhất x=0

Phương trình có nghiệm duy nhất x=1/3

Phương trình có nghiệm duy nhất x=2/3

Các câu trên đều sai

0

1/2

1

3/2

Điểm uốn tại -2

Điểm uốn tại 1

Điểm uốn tại e

Điểm uốn tại 0

y tăng trên$$(0,+\infty )$$, giảm trên$$(-\infty ,0)$$

y tăng trên$$(-\infty ,1)$$, giảm trên$$(2,+\infty )$$

y luôn tăng

y luôn giảm

$$8-4\sqrt{2}$$

$$2({\mathrm{e}}^2-1)$$

$$2{\mathrm{e}}^2$$

2

$$-\cot \frac{x}{2}$$

$$\cot \frac{x}{2}$$

$$-\frac{1}{2}\cot g\frac{x}{2}$$

$$-2\cot g\frac{x}{2}$$

1

2

-2

-3

$$\mathrm{tg}\frac{\mathrm{x}}{2}$$

$$-\frac{1}{2}\mathrm{tg}\frac{\mathrm{x}}{2}$$

$$-2\mathrm{tg}\frac{\mathrm{x}}{2}$$

$$\frac{1}{\sqrt{2}}\mathrm{arctg}\left(\frac{\mathrm{tgx}}{\sqrt{2}}\right)+\mathrm{C}$$

$\sqrt{2}\mathrm{arctg}\left(\frac{\mathrm{tgx}}{\sqrt{2}}\right)+\mathrm{C}$

$-\sqrt{2}\mathrm{arctg}\left(\frac{\mathrm{tgx}}{\sqrt{2}}\right)+\mathrm{C}$

$-\frac{1}{\sqrt{2}}\mathrm{arctg}\left(\frac{\mathrm{tgx}}{\sqrt{2}}\right)+\mathrm{C}$

$$(\mathrm{x}-1){\mathrm{e}}^{-\mathrm{x}}$$

$$(\mathrm{x}+1){\mathrm{e}}^{-\mathrm{x}}$$

$-(\mathrm{x}+1){\mathrm{e}}^{-\mathrm{x}}$

$$(-\mathrm{x}+1){\mathrm{e}}^{-\mathrm{x}}$$

$$\mathrm{I}=\frac{4({\mathrm{x}}^2+5)}{7\sqrt[4]{\mathrm{x}}}+\mathrm{C}$$

$$\mathrm{I}=\frac{3({\mathrm{x}}^2+7)}{7\sqrt[3]{\mathrm{x}}}+\mathrm{C}$$

$$\mathrm{I}=\frac{3({\mathrm{x}}^2+7)}{7\sqrt[4]{\mathrm{x}}}+\mathrm{C}$$

$$\mathrm{I}=\frac{4({\mathrm{x}}^2+7)}{7\sqrt[4]{\mathrm{x}}}+\mathrm{C}$$

$$\mathrm{I}=\frac{1}{2}{\mathrm{e}}^{2x}-{\mathrm{e}}^{\mathrm{x}}+\mathrm{x}+\mathrm{C}$$

$$\mathrm{I}=\frac{1}{2}{\mathrm{e}}^{2x}-{\mathrm{e}}^{-\mathrm{x}}+\mathrm{x}+\mathrm{C}$$

$$\mathrm{I}=\frac{1}{3}{\mathrm{e}}^{3x}-{\mathrm{e}}^{-\mathrm{x}}+\mathrm{x}+\mathrm{C}$$

$$\mathrm{I}=\frac{1}{2}{\mathrm{e}}^{2x}+{\mathrm{e}}^{-\mathrm{x}}+\mathrm{x}+\mathrm{C}$$

$$\mathrm{I}=-\mathrm{arctg}({\mathrm{e}}^{\mathrm{x}})+\mathrm{C}$$

$$\mathrm{I}=\mathrm{arctg}({\mathrm{e}}^{\mathrm{x}})+\mathrm{C}$$

$$\mathrm{I}=\mathrm{arctg}({\mathrm{e}}^{-\mathrm{x}})+\mathrm{C}$$

$$\mathrm{I}=\frac{1}{2}\mathrm{arctg}({\mathrm{e}}^{\mathrm{x}})+\mathrm{C}$$